Optimal. Leaf size=41 \[ \frac{\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)}{c}-\frac{\text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{2 c} \]
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Rubi [A] time = 0.0646014, antiderivative size = 41, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.176, Rules used = {1593, 5932, 2447} \[ \frac{\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)}{c}-\frac{\text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{2 c} \]
Antiderivative was successfully verified.
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Rule 1593
Rule 5932
Rule 2447
Rubi steps
\begin{align*} \int \frac{\tanh ^{-1}(a x)}{c x+a c x^2} \, dx &=\int \frac{\tanh ^{-1}(a x)}{x (c+a c x)} \, dx\\ &=\frac{\tanh ^{-1}(a x) \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{a \int \frac{\log \left (2-\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{c}\\ &=\frac{\tanh ^{-1}(a x) \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{\text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{2 c}\\ \end{align*}
Mathematica [A] time = 0.0736186, size = 39, normalized size = 0.95 \[ \frac{\tanh ^{-1}(a x) \log \left (1-e^{-2 \tanh ^{-1}(a x)}\right )}{c}-\frac{\text{PolyLog}\left (2,e^{-2 \tanh ^{-1}(a x)}\right )}{2 c} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.045, size = 126, normalized size = 3.1 \begin{align*}{\frac{{\it Artanh} \left ( ax \right ) \ln \left ( ax \right ) }{c}}-{\frac{{\it Artanh} \left ( ax \right ) \ln \left ( ax+1 \right ) }{c}}+{\frac{1}{2\,c}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }-{\frac{\ln \left ( ax+1 \right ) }{2\,c}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) }+{\frac{1}{2\,c}{\it dilog} \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{ \left ( \ln \left ( ax+1 \right ) \right ) ^{2}}{4\,c}}-{\frac{{\it dilog} \left ( ax \right ) }{2\,c}}-{\frac{{\it dilog} \left ( ax+1 \right ) }{2\,c}}-{\frac{\ln \left ( ax \right ) \ln \left ( ax+1 \right ) }{2\,c}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.961415, size = 162, normalized size = 3.95 \begin{align*} \frac{1}{4} \, a{\left (\frac{\log \left (a x + 1\right )^{2}}{a c} - \frac{2 \,{\left (\log \left (a x + 1\right ) \log \left (-\frac{1}{2} \, a x + \frac{1}{2}\right ) +{\rm Li}_2\left (\frac{1}{2} \, a x + \frac{1}{2}\right )\right )}}{a c} - \frac{2 \,{\left (\log \left (a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (-a x\right )\right )}}{a c} + \frac{2 \,{\left (\log \left (-a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (a x\right )\right )}}{a c}\right )} -{\left (\frac{\log \left (a x + 1\right )}{c} - \frac{\log \left (x\right )}{c}\right )} \operatorname{artanh}\left (a x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{artanh}\left (a x\right )}{a c x^{2} + c x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\operatorname{atanh}{\left (a x \right )}}{a x^{2} + x}\, dx}{c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{artanh}\left (a x\right )}{a c x^{2} + c x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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